已知a-b=3,ab=1,化简(a+2)(b-2)的结果是

问题描述:

已知a-b=3,ab=1,化简(a+2)(b-2)的结果是

把括号打开可得:
ab-2a+2b-4
=ab-2(a-b)-4(由题可知a-b=3,ab=1,所以代入式中,可得)
=1-6-4
= -9

(a+2)(b-2)=ab-2a+2b-1=ab-2(a-b)-1=1-6-1=-6

(a+2)(b-2)
=ab-2a+2b-4
=ab-2(a-b)-4
=1-2×3-4
=-9