稀h2so4和baoh2离子咋错了?h+so4+ba+oh=baso4+2h2o
问题描述:
稀h2so4和baoh2离子咋错了?h+so4+ba+oh=baso4+2h2o
答
给氢离子、氢氧根都填上系数2,并注明所有离子的电荷就对了 2h+so4+ba+2oh=baso4+2h2o
稀h2so4和baoh2离子咋错了?h+so4+ba+oh=baso4+2h2o
给氢离子、氢氧根都填上系数2,并注明所有离子的电荷就对了 2h+so4+ba+2oh=baso4+2h2o