1.8x[6又5/12除以16+(9-2又7/12)]除以2又3/4
问题描述:
1.8x[6又5/12除以16+(9-2又7/12)]除以2又3/4
答
1.8×[6又5/12÷16+(9-2又7/12)]÷2又3/4原式=1.8×[6又5/12÷16+(8又12/12-2又7/12)]÷2又3/4=1.8×(6又5/12÷16+6又5/12)÷2又3/4=1.8×(6又5/12×1/16+6又5/12×1)÷2又3/4=1.8×6又5/12×(1/16+1)÷2又3/4...