16(3x+2)²=25(2x-3)²
问题描述:
16(3x+2)²=25(2x-3)²
答
16(3x+2)²-25(2x-3)²=0
(4(3x+2)+5(2x-3))(4(3x+2)-5(2x-3))=0
(22x-7)(2x+23)=0
x=7/22或者x=-23/2
答
16(3x+2)²=25(2x-3)²
16(3x+2)² -25(2x-3)² =0
[4(3x+2)+5(2x-3)][4(3x+2)-5(2x-3)] =0
[22x-7][2x+23] =0
x=7/22 x=-23/2
答
16(3x+2)²=25(2x-3)²
16(3x+2)²-25(2x-3)²=0
【4(3x+2)-5(2x-3)】【4(3x+2)+5(2x-3)】=0
(2x+23)(22x-7)=0
2x+23=0 或22x-7=0
x= -23/2或x=7/22