(1)已知(1/x) -(1/y)=3,则代数式(2x-14xy-2y)/(x-2xy-y)的值为_____.(2)若1/x(x+1)=(A/x)+(B/x+1),则A=_______,B=_______.(3)分解因式:(2x)/(x^-4)+3/(x+2)+1/(2-x);
问题描述:
(1)已知(1/x) -(1/y)=3,则代数式(2x-14xy-2y)/(x-2xy-y)的值为_____.
(2)若1/x(x+1)=(A/x)+(B/x+1),则A=_______,B=_______.
(3)分解因式:(2x)/(x^-4)+3/(x+2)+1/(2-x);
答