解三元一次方程组x+2+y+z=10,2x+3y-z=3,3x+2y+2z=17
问题描述：
解三元一次方程组x+2+y+z=10,2x+3y-z=3,3x+2y+2z=17
x+2+y+z=10,
{2x+3y-z=3,
3x+2y+2z=17
答
x+2+y+z=10,------- ①2x+3y-z=3,------- ②3x+2y+2z=17------- ③①+②3x+4y+2 = 133x+4y = 11------- ④②×2 + ③7x+8y = 23------- ⑤⑤×2 - ④x = 1代入④3 + 4y = 11y = 2将x = 1、y = 2代入①1+2+2+z = 10z ...