x的平方-9分之6+x+3分之1=多少?
问题描述：
x的平方-9分之6+x+3分之1=多少?
答
原式=6/(x+3)(x-3)+(x-3)/(x+3)(x-3)
=(6+x-3)/(x+3)(x-3)
=(x+3)/(x+3)(x-3)
=1/(x-3)