计算:cos45°+sin30°sin30°•tan45°+tan260°−2tan60°+1.
问题描述:
计算:
+cos45°+sin30° sin30°•tan45°
.
tan260°−2tan60°+1
答
原式=
+1+
+
2
2
1 2
1 2
(tan60°−1)2
=
+1+
2
-1
3
=
+
2
.
3