把下列各式化成最简二次根式: (1)27/5132−12227; (2)−abc/2c32a4b.
问题描述:
把下列各式化成最简二次根式:
(1)
27 5
;
132−122
27
(2)−
abc 2
.
c3 2a4b
答
(1)原式=
27 5
=
25 27
×27 5
×5 3
=9
1 3
=3
1 3
;
3
(2)原式=-
×abc 2
×|c| a2
=−
c 2b
c2 4a
.
2bc