用代入消元法解二元一次方程组:x+y/2+x-y/3=1 (1) (x+y)-5(x-y)=2 (2)
问题描述:
用代入消元法解二元一次方程组:x+y/2+x-y/3=1 (1) (x+y)-5(x-y)=2 (2)
答
x+y/2+x-y/3=1
3(x+y)+2(x-y)=1
5x+y=1
y=1-5x
(x+y)-5(x-y)=2
6y-4x=2
6(1-5x)-4x=2
6-30x-4x=2
34x=4
x=2/17
y=1-5x2/17=7/17
如果本题有什么不明白可以追问,