化简 3a-{2c-【6a-(c-b)+c+(a+8b-9c)】} (3a的平方-ab+1)-(4a的平方+6ab+7)
问题描述:
化简 3a-{2c-【6a-(c-b)+c+(a+8b-9c)】} (3a的平方-ab+1)-(4a的平方+6ab+7)
3a-{2c-【6a-(c-b)+c+(a+8b-9c)】}
(3a的平方-ab+1)-(4a的平方+6ab+7)
答
3a-{2c-【6a-(c-b)+c+(a+8b-9c)】}
=3a-2c+6a-c-b-c-a-8b+9c
=8a-9b+5c
(3a的平方-ab+1)-(4a的平方+6ab+7)
=3a²-ab+1-4a²-6ab-7
=-a²-7ab-6