方程log(x+1)|x^2-x-1|=1的解集
问题描述：
方程log(x+1)|x^2-x-1|=1的解集
答
log(x+1,x^2-x-1)=1log(x^2-x-1)=log(x+1)log(x^2-x-1)-log(x+1)=0log((x^2-x-1)/(x+1))=0(x^2-x-1)/(x+1)=1x^2-x-1=x+1x^2-2x+1=3(x-1)^2=3x=1+sqrt(3)或x=1-sqrt(3)解集：x∈{1+sqrt(3),1-sqrt(3)}