先化简,再求值:(x+1-3/(x-1))÷(x平方-4x+4)/(x-1),求组x满足方程:x平方+x-6=0

问题描述:

先化简,再求值:(x+1-3/(x-1))÷(x平方-4x+4)/(x-1),求组x满足方程:x平方+x-6=0

由x²+x-6=0解得x1=2,x2=-3,(x+1-3/(x-1))÷(x平方-4x+4)/(x-1)=(X-2)(X+2)/[(x+1)(x-1)]*(x-1)/(x-2)²=(X+2)/[(X+1)(X-2)]当X=2时,原式无意义;当X=-3时,原式=(-3+2)/[(-3+1)(-3-2)]=-1/10...