已知A=5a+3b,B=3a2-2a2b,C=a2+7a2b-2,当a=1,b=2时,求A-2B+3C的值.

问题描述:

已知A=5a+3b,B=3a2-2a2b,C=a2+7a2b-2,当a=1,b=2时,求A-2B+3C的值.

∵A=5a+3b,B=3a2-2a2b,C=a2+7a2b-2,
∴A-2B+3C=(5a+3b)-2(3a2-2a2b)+3(a2+7a2b-2)
=5a+3b-6a2+4a2b+3a2+21a2b-6
=-3a2+25a2b+5a+3b-6,
当a=1,b=2时,原式=-3×12+25×12×2+5×1+3×2-6=52.