室温下向10ml ph=3的醋酸溶液中加水稀释(CH3COOH-)/(c(CH3COO+)·c(OH-))的比值不变
问题描述：
室温下向10ml ph=3的醋酸溶液中加水稀释(CH3COOH-)/(c(CH3COO+)·c(OH-))的比值不变
答
CH3COOH ==可逆== H+ + CH3COO-
Ka = c(H+) * c(CH3COO-) / c(CH3COOH),
平衡常数Ka只与温度有关,与其他因素无关.
温度不变,Ka不变,
所以c(CH3COOH)÷ [c(H+) * c(CH3COO-)] = 1/Ka 也不变
所以c(CH3COOH)÷ [ Kw/c(OH-) * c(CH3COO-)] 不变所以c(CH3COOH)÷ [ Kw/c(OH-) * c(CH3COO-)] 不变不懂？