已知4x2-4x+1+3y-2=0,求x+y的值.

问题描述:

已知4x2-4x+1+

3y-2
=0,求x+y的值.

4x2-4x+1+

3y-2
=0,即(2x-1)2+
3y-2
=0,
∵(2x-1)2≥0,
3y-2
≥0,
∴2x-1=0,且3y-2=0,即x=
1
2
,y=
2
3

则x+y=
1
2
+
2
3
=1
1
6