计算:1/3a-(1/2a-4b-6c)+3(-2c+2b)=_.

问题描述:

计算:

1
3
a-(
1
2
a-4b-6c)+3(-2c+2b)=______.

1
3
a-(
1
2
a-4b-6c)+3(-2c+2b),
=
1
3
a-
1
2
a+4b+6c-6c+6b,
=(
1
3
1
2
)a+(4+6)b+(6-6)c,
=-
1
6
a+10b.
故答案为:-
1
6
a+10b.