已知二元一次方程组{2x+y=7;x+2y=8,则x-y=____,x+y=___
问题描述:
已知二元一次方程组{2x+y=7;x+2y=8,则x-y=____,x+y=___
答
x-y
=(2x+y)-(x+2y)
=7-8
=-1
x+y
=[(2x+y)+(x+2y)]÷3
=(7+8)÷3
=5