函数f(x)=sinxcosx+根号3cos^2x-根号3/2
问题描述:
函数f(x)=sinxcosx+根号3cos^2x-根号3/2
最小正周期 最大值 增区间
答
f(x)=sinxcosx+√3(cosx)^2-√3/2
=(1/2)sin2x+(√3/2)cos2x
=sin2xcosπ/3+cos2xsinπ/3
=sin(2x+π/3)