化简:(cos10°+根号下3sin10°)/根号下(1-cos80°)=
问题描述:
化简:(cos10°+根号下3sin10°)/根号下(1-cos80°)=
分子上的那个 应该是 :(cos10°+√3*sin10°)
答
(cos10°+根号下3sin10°)/根号下(1-cos80°)
=2sin(10+30)度/根号下(1-(1-2sin^2(40))
=2sin40度/(根号2*sin40度)
=根号2