已知4x2+y2-4x+10y+26=0,求6x-1/5y的值.

问题描述:

已知4x2+y2-4x+10y+26=0,求6x-

1
5
y的值.

∵4x2+y2-4x+10y+26=4(x-

1
2
2+(y+5)2=0,
∴x=
1
2
,y=-5,
则原式=3+1=4.