已知[(x2+y2)-(x-y)2+2y(x-y)]÷4y=1,求4x/4x2−y2-1/2x+y的值.
问题描述:
已知[(x2+y2)-(x-y)2+2y(x-y)]÷4y=1,求
-4x 4x2−y2
的值. 1 2x+y
答
[(x2+y2)-(x-y)2+2y(x-y)]÷4y=(x2+y2-x2+2xy-y2+2xy-2y2)÷4y=(4xy-2y2)÷4y=x-12y∵x-12y=1,∴2x-y=2,∴4x4x2−y2-12x+y,=4x(2x+y)(2x−y)-12x+y=4x−2x+y(2x+y)(2x−y)=2x+y(2x+y)(2x−y)=12x−y=12...