5道因式分解题,
问题描述：
5道因式分解题,
1.x^2-4x-12=0
2.y(y+5=-25/4
3.3(x-3)=(x-3)^2
4.(2x+3)^2=24x
5.1.2y-0.04=9y^2
答
1.x^2-4x-12=0(x-6)(x+2)=0x=6或x=-22.y(y+5)=-25/4y^2+5y+25/4=0(y+5/2)^2=0y=-5/23.3(x-3)=(x-3)^2(x-3)^2-3(x-3)=0(x-3)(x-3-3)=0(x-3)(x-6)=0x=3或x=64.(2x+3)^2=24x(2x+3)^2-24x=04x^2+12x+9-24x=04x^2-12x+9=0...