计算:(2003+1/2)-(2002+1/3)+(2001+1/2)-(2000+1/3)……+(1+1/2)-1/3

问题描述:

计算:(2003+1/2)-(2002+1/3)+(2001+1/2)-(2000+1/3)……+(1+1/2)-1/3

(2003+1/2)-(2002+1/3)+(2001+1/2)-(2000+1/3)……+(1+1/2)-1/3
=(2003-2002)+(2001-2000)+……(1-0)+(1/2-1/3)×1002
=1002+(1/6×1002)
=1002+167
=1169