分解因式2a(x²+1）²-2ax² 2x²+2x+1/2

分类: 作业答案 • 2021-12-18 16:30:32

问题描述：

答

2a(x²+1)²-2ax²
=2a[(x²+1)²-x²]
=2a(x²+x+1)(x²-x+1)
2x²+2x+1/2
=2(x²+x +1/4)
=2(x+1/2)²

答

2a(x²+1）²-2ax²
=2a((x^2+1)^2-x^2)
=2a(x^2+1-x)(x^2+1+x)

2x²+2x+1/2
=(1/2)(4x^2+4x+1)
=(1/2)(2x+1)^2

答

2a(x²+1）²-2ax²
=2a[(x²+1)²-x²]
=2a(x²+1+x)(x²+1-x)
2x²+2x+1/2
=1/2(4x²+4x+1)
=1/2(2x+1)²
如果本题有什么不明白可以追问,

答

2a(x²+1）²-2ax² =2a(x²+1-x)(x²+1+x)
2x²+2x+1/2=(1/2)(2x+1)²