计算(x^2+2x+1/x+2)/(x^2-1/x^2+2x)*(x-1/x),并求当x=-3/2时的值
问题描述：
计算(x^2+2x+1/x+2)/(x^2-1/x^2+2x)*(x-1/x),并求当x=-3/2时的值
答
原式=[(x+1)^2/(x+2)]×[x(x+2)/x^2-1)]×[(x^2-1)/x]
=x(x+2)(x+1)^2(x^2-1)/[x(x+2)(x^2-1)]
=(x+1)^2
=(-3/2+1)^2
=1/4