一元二次方程3x^2+2x-2=3(x+)^2+()

分类: 作业答案 • 2021-11-12 22:41:01

问题描述：

一元二次方程3x^2+2x-2=3(x+__)^2+(__)
后面那个空到底填-16/3 还是 -7/3?别忘了等式后面是等于3

答

先都提取3
则3x^2+2x-2
=3(x²+2/3x-2/3)
=3(x²+2/3x+1/9-1/9-2/3)
=3(x²+2/3x+1/9)-3(1/9+2/3)
=3(x+1/3)²-7/3

一元二次方程3x^2+2x-2=3(x+__)^2+(__)