用试根法因式分解：①x^4+3x^3-3x^2-11x-6②x^6+2x^5+3x^4+4x^3+3x^2+2x+1

x^4+3x^3-3X^2-11x-6 =x^3(x+3)-(3x^2+11x+6)=x^3(x+3)-(x+3)*(3x+2)=(x+3)(x^3-3x-2)=(x+3)[x^3-x-2(x+1)]=(x+3)[x(x+1)(x-1)-2(x+1)]=(x+3)(x+1)(x^2-x-2)=(x+3)(x-2)(x+1)^2x^6+2x^5+3x^4+4x^3+3x^2+2x+1=x^6+x^5...