-8a(a+1)平方+2a的3次方
问题描述:
-8a(a+1)平方+2a的3次方
答
-8a(a+1)平方+2a的3次方
=2a[a²-4(a+1)²]【说明4(a+1)²=[2(a+1)]²】
=2a[a+2(a+1)][a-2(a+1)]
=2a(3a+2)(﹣a-2)
=﹣2a(3a+2)(a+2)