因式分解:3A^2-6A+3若|A-2|+B^2-2B+1=0则A=_______
问题描述:
因式分解:3A^2-6A+3
若|A-2|+B^2-2B+1=0则A=_______
答
=3(A^2 -2A + 1)
=3(A-1)^2
答
3A^2-6A+3=3(A-1)^2
|A-2|+(B-1)^2=0
A=2
答
3A^2-6A+3=3(A^2-2A+1)=3(A-1)^2
|A-2|+B^2-2B+1=0
|A-2|+(B-1)^2=0
A-2=0,B-1=0
A=2