(2a-b+c)的平方 怎么算
问题描述：
(2a-b+c)的平方 怎么算
答
(2a-b+c)^2
=[2a-(b-c)]^2
=4a^2-4a(b-c)+(b-c)^2
=4a²+b²+c²-4ab-2bc+4ac
答
=4a²+b²+c²-4ab-2bc+4ac
答
(2a-b+c)^2
=[2a-(b-c)]^2
=4a^2-4a(b-c)+(b-c)^2
=4a^2-4ab+4ac+b^2-2bc+c^2