将√3/2cosx+1/2sinx化为Acos(ωx+φ)(A>0,ω>0,|φ|
问题描述:
将√3/2cosx+1/2sinx化为Acos(ωx+φ)(A>0,ω>0,|φ|
答
√3/2cosx+1/2sinx=sin60°*cosx+cos60°*sinx
=sin(x+60°)=cos(x+30°)