x^2-6x+9/x^2-x-6 * x^2-7x+10/x^2-9 * x+3/2(x-5)怎么算?
问题描述：
x^2-6x+9/x^2-x-6 * x^2-7x+10/x^2-9 * x+3/2(x-5)怎么算?
答
原式=(x-3)^2/【(x-3)*(x+2)】*(x-2)(x-5)/【(x+3)(x-3)】*(x+3)/【2(x-5)】=(x-2)/【2(x+2)】