0.13(10-x)+0.17(10-2x)+0.22(10-3x)+0.28(10-4x)=2
问题描述：
0.13(10-x)+0.17(10-2x)+0.22(10-3x)+0.28(10-4x)=2
答
分别向城 合并同类项后会得到2.25X=6 ；在相除可以得到X=8/3.(2.666666666666666 6循环)
答
0.13(10-x)+0.17(10-2x)+0.22(10-3x)+0.28(10-4x)=2
1.3+1.7+2.2+2.8-x(0.13+0.34+0.66+1.12)=2
8-2.25x=2
2.25x=6
x=8/3
答
0.13(10-x)+0.17(10-2x)+0.22(10-3x)+0.28(10-4x)=2
1.3-0.13x+1.7-0.34x+2.2-0.66x+2.8-1.12x=2
(0.13+0.34+0.66+1.12)x=1.3+1.7+2.2+2.8-2
2.25x=6
x=6÷2.25
x=8/3