The big hill on a roller coaster ride is 91.0m high.If the mass of the roller coaster and its two riders is 314.0kg and the maximum velocity reached by this roller coaster ride is 28.0 m/s,how much Kinetic Energy is lost in the system?
The big hill on a roller coaster ride is 91.0m high.If the mass of the roller coaster and its two riders is 314.0kg and the maximum velocity reached by this roller coaster ride is 28.0 m/s,how much Kinetic Energy is lost in the system?
最大的山在坐过山车是91.0米高。如果过山车的质量和它的两个骑士是314.0公斤,这个过山车达成的最大速度是28.0米/秒,系统的动能损失多少
过山车的最陡斜坡有91米高，假设过山车和两个坐过山车的人的质量是314kg，且过山车的速度达到最快速度28m/s，那么系统动能损失多少？
翻译：在过山车的大山是91.0米高.如果过山车和它的两个车手的质量是314.0千克并以此坐过山车达到的最大速度28.0米/秒,有多少动能损失在系统中?
根据能量守恒定律：重力势能=动能+损失能量
E(lost)=Ep-Ev=mgh-1/2mV^2=314.0*9.8*91.0-1/2*314.0*28.0^2
=280025.2-123088=156937.2J
在坐过山车的大山是91.0米高。如果过山车和它的两个车手的质量是314.0千克并以此坐过山车达到的最大速度28.0米/秒，有多少动能损失在系统中？
由于能量是守恒的
开始的能量Eo=mgh=314.0kg*9.8N/kg*91.0m
E损=Eo-E动=Eo-1/2*mv2=314.0kg*9.8N/kg*91.0m-1/2*314.0*28.0*28.0