因式分解x²-64,x²-6xy²+9y³,解方程组7x+3y=13,4x-y=2要过程

1. x²-64=(X+8)(X-2√2)(X+2√2)

   x²-6xy²+9y⁴=(X-3Y²)²

2. 7x+3y=13   (1)

   4x-y=2  (2)

   (1)-(2)*3得:19x=19

   x=1

   代入（2）得:y=2

   
   

分解x²-64,
=(x+8)(x-8)
x²-6xy²+9y³,
=(x+3)²
解方程组
7x+3y=13, ①
4x-y=2 乘以3 得 12x -3y = 6 ②
①+② 得
19x = 19
x = 1
y = 4x - 2 = 2

x²-64,=（x-8)(x+8) x²y-6xy²+9y³=y(x²-6xy+9y²)=y(x-3y)² 7x+3y=13, ①4x-y=2 ②①+②×3得：7x+3y+12x-3y=13+619x=19∴x=1 y=2