(2x-1)²-x²=0 x²-6x+9=(5-2x)²
问题描述：
(2x-1)²-x²=0 x²-6x+9=(5-2x)²
答
(2x-1)²-x²=0
(2x-1+x)(2x-1-x)=0
(3x-1)(x-1)=0
x=1/3或x=1
x²-6x+9=(5-2x)²
(x-3)²-(5-2x)² =0
(x-3+5-2x)(x-3-5+2x)=0
(2-x)(3x-8)=0
x=2或x=8/3
答
(2x-1)²-x²=0（2x-1+x）（2x-1-x）=0(3x-1)(x-1)=0x1=1/3 x2=1x²-6x+9=(5-2x)² (x-3)²-(5-2x)²=0(x-3+5-2x)(x-3-5+2x)=0(2-x)(3x-8)=0x1=2 x2=8/3