解二元一次方程组2x+3y/2=3x+2y/5+2 3（2x+3y）/2=2（3x+2y）/5+6
问题描述：
解二元一次方程组2x+3y/2=3x+2y/5+2 3（2x+3y）/2=2（3x+2y）/5+6
答
(2x+3y)/2=(3x+2y)/5+2 ① 3(2x+3y)/2=2(3x+2y)/5+6 ②①得,2x+3y=2(3x+2y)/5+4 ③代入②得,3（3x+2y)/5+6=2(3x+2y)/5+63x+2y=0x=-2y/3④代入③得,-4y/3+3y=4y=12/5代入④,得 x=-8/5∴方程组的解是：x=-8/5y=12/5...