通分：6-2x分之x-1和x²-9分之6和x²-9和x²+6x+9要过程
问题描述：
通分：6-2x分之x-1和x²-9分之6和x²-9和x²+6x+9要过程
答
(x-1)/(6-2x)=(x-1)/(-2(x-3))=(1-x)6/2(x-3)^2=3(1-x)/(x-3)^26/x^2-9=6/(x+3)(x-3)=6(x+3)/2(x+3)(x-3)^2=3(1-x)/(x-3)^2x^2+6x+9=(x+3)^2=3(1-x)(x+3)^2/(x+3)(x-3)^2=3(1-x)/(x-3)^2