x2-(p2+q2)x+pq(p+q)(p-q),x2-2xy-8y2-x-14y-6,这2道体求因式分解,（字母后为平方）

1.x^2-(p^2+q^2)x+pq(p+q)(p-q)=x^2-(p^2+q^2)x+pq(p^2-q^2)=x^2-(p^2+q^2)x+pq(p-q)(p+q)=x^2-(p^2+q^2)x+(p^2-pq)(pq+q^2) x^2-(p^2+q^2)x+(p^2-pq)(pq+q^2)=[x-(p^2-pq)][x-(pq+q^2)]=(x-p^2+pq)(x-pq-q^2) 2.x2-...