a的3次方-3a+2因式分解 视情况会给分
问题描述：
a的3次方-3a+2因式分解 视情况会给分
答
=a^3-1-3(a-1)
=(a-1)(a^2+a+1)-3(a-1)
=(a-1)(a^2+2)
答
a^3-3a+2=(a^3-a)-(2a-2)=a(a^2-1)-2(a-1)=a(a+1)(a-1)-2(a-1)=(a-1)(a^2+a-2)=(a-1)(a+2)(a-1)
=(a-1)^2(a+2)
答
a^3-3a+2
=a^3+a^2-2a-a^2-a+2
=a(a^2+a-2)-(a^2+a-2)
=(a-1)(a^2+a-2)
望采纳
答
a^3-3a+2
=a^3-3a-1+3
=(a^3-1)-(3a-3)
=(a-1)(a^2+a+1)-3(a-1)
=(a-1)(a^2+a-2)
=(a-1)(a-1)(a+2)
=(a-1)^2(a+2)
答
a^3-3a+2
=a^3-1-(3a-3)
=(a-1)(a^2+a+1)-3(a-1)
=(a-1)(a^2+a-2)
=(a-1)^2×(a+2)
答
(a-1)(a-1)(a+2)