3y+5/3y-6=(1/2)+(5y-4/2y-4)等于多少?
问题描述：
3y+5/3y-6=(1/2)+(5y-4/2y-4)等于多少?
答
(3y+5)/(3y-6) = 1/2 + (5y-4)/(2y-4)(3y+5)/(3y-6) - (5y-4)/(2y-4)= 1/2(3y+5)/{3(y-2)} - (5y-4)/{2(y-2)} = 1/2{ 2(3y+5) - 3 (5y-4) } / {6(y-2) } = 1/2{ 6y+10 - 15y+12 } = 3(y-2)-9y+22=3y-612y=28y=14/11