如果复数满足(1+2i)z(ba)=4+3i,求z=?写过程
问题描述：
如果复数满足(1+2i)z(ba)=4+3i,求z=?
写过程
答
z(ba)是说z的共轭吧。
z(ba)=(4+3i)/(1+2i)
=(4+3i)(1-2i)/5
=2-i
所以z=2+i
答
Z=(4+3i)/(1+2i)
=(4+3i)(1-2i)/(1+2i)(1-2i)
=(4-8i+3i+6)/(1+4)
=(10-5i)/5
=2-i