化为平方差的形式再因式分解1.x^4-3x^2y^2+y^42.64x^4+1
问题描述：
化为平方差的形式再因式分解
1.x^4-3x^2y^2+y^4
2.64x^4+1
答
1.x^4-3x^2y^2+y^4=x^4-2x^2y^2+y^4-x^2y^2=(x^2-y^2)^2-x^2y^2=(x^2-y^2+xy)(x^2-y^2-xy)2.64x^4+1=64x^4+16x^2+1-16x^2=(8x^2+1)-16x^2=(8x^2+1+4x)(8x^2+1-4x)