·甲商品连续两次降价10%乙连续一次涨价10%,后来售价都为m元则两位原价是多少
问题描述:
·甲商品连续两次降价10%乙连续一次涨价10%,后来售价都为m元则两位原价是多少
答
乙:m/(1+10%).甲:m/(1+10%)*(1+10%)*(1+10%)=m(1+10%)
·甲商品连续两次降价10%乙连续一次涨价10%,后来售价都为m元则两位原价是多少
乙:m/(1+10%).甲:m/(1+10%)*(1+10%)*(1+10%)=m(1+10%)