[(3x-1/2y^2)+3y(x-y/12)]÷[(2x+y)^2-4y(x+1/4y)]

问题描述:

[(3x-1/2y^2)+3y(x-y/12)]÷[(2x+y)^2-4y(x+1/4y)]

原式=(9x^2-3xy+1/4y^2+3xy-1/4y^2)÷(4x^2+4xy+u^2-4xy-y^2)
=9x^2÷4x^2
=9/4