如果|3x+2y-4|与(5x+7y-3)²互为相反数,求x+y的值
问题描述:
如果|3x+2y-4|与(5x+7y-3)²互为相反数,求x+y的值
答
|3x+2y-4|与(5x+7y-3)²互为相反数,
而|3x+2y-4|≥0与(5x+7y-3)²≥0
所以
|3x+2y-4|=0
(5x+7y-3)²=0
3x+2y-4=0
5x+7y-3=0
得
x=2,y=-1
x+y=1