解方程(6/5x+0.5)^-(1.2x-1/2)^2=-24

问题描述:

解方程(6/5x+0.5)^-(1.2x-1/2)^2=-24

f(x)=cos2x+1+√3sin2x
=2(sin2xcosπ/6+cos2xsinπ/6)+1
=2sin(2x+π/6)+1
sin(2x+π/6)递增则2kπ-π/22kπ-2π/3kπ-π/3所以增区间是(kπ-π/3,kπ+π/6)

(1.2x+0.5)^2-(1.2x-0.5)^2=-24
(1.2x+0.5+1.2x-0.5)(1.2x+0.5-1.2x+0.5)=-24
2.4x=-24
x=-10