已知x+y=3,xy=-12,x^2-xy+y^2
问题描述:
已知x+y=3,xy=-12,x^2-xy+y^2
答
x^2-xy+y^2
=x^2+2xy+y^2-3xy
=(x+y)^2-3xy
=3^2-3*(-12)
=9+36
=45
答
45
答
原式=x^2+2xy+y^2-3xy
=(x+y)^2-3xy
=3^2-3*(-12)
=9+36
=45