已知x+y=3,xy=-12,x^2-xy+y^2

问题描述:

已知x+y=3,xy=-12,x^2-xy+y^2

x^2-xy+y^2
=x^2+2xy+y^2-3xy
=(x+y)^2-3xy
=3^2-3*(-12)
=9+36
=45

45

原式=x^2+2xy+y^2-3xy
=(x+y)^2-3xy
=3^2-3*(-12)
=9+36
=45