计算题哈,若代数式x^2+y^2-14x+2y+50的值为0.化简求值：[2x^2-(x+y)(x-y)]-[(-x-y)(-x+y)+2y^2]请把每一步写清楚了,

如果使代数式x^2+y^2-14x+2y+50的值为0,则x^2+y^2-14x+2y+50=0 (x-7)^2+(y+1)^2=0 x=7,y=-1 [2x^2-(x+y)(x-y)]-[(-x-y)(-x+y)+2y^2] =[2x^2-(x^2-y^2)]-[(x^2-y^2)+2y^2] =(x^2+y^2)-(x^2+y^2)=x^2+y^2-x^2-y^2=0(好...